Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCalculate of COMEasy2 minQB

PhysicsEasyinteger

Find the magnitude of $x$ coordinate of centre of mass of the system.

Answer:

Solution:

**Solution:**

Given:

$m_{1} = 8 k g, x_{1} = - 4 m$

$m_{2} = 4 k g, x_{2} = + 2 m$

The $x$ -coordinate of the center of mass is:

$x_{CM} = \frac{m _{1} x _{1} + m _{2} x _{2}}{m _{1} + m _{2}}$

$x_{CM} = \frac{8 ( - 4 ) + 4 ( 2 )}{8 + 4}$

$= \frac{- 32 + 8}{12} = \frac{- 24}{12} = - 2 m$

Hence, the **magnitude** of the $x$ -coordinate is:

$∣ x_{CM} ∣ = 2 m$

**Answer:** $2 m$

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Calculate of COM

⏱ 2mℹ️ Source: QB

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