Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsMedium2 minQB

PhysicsMediumsingle choice

A ring of radius R is rolling purely on the outer surface of a pipe of radius 4R. At some instant, the center of the ring has a constant speed $= v$ . Then , the acceleration of the point on the ring which is in contact with the surface of the pipe is :

Options:

Answer:

Solution:

$a_{A} = a_{A / c m} + a_{c m}$

$a_{cm} = \frac{v ^{2}}{5 R} ↓$

$a_{A/cm} = R ω^{2} = \frac{v ^{2}}{R} ↑$

$a_{A} = (\frac{v ^{2}}{R} - \frac{v ^{2}}{5 R}) ↑= \frac{4 v ^{2}}{5 R} ↑$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: QB

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