A uniform rod of mass m and length ℓ is in equilibrium under the action of contact forces, gravity and tension in string as shown in the figure. LIST I LIST II (P) The tension is the string is (1) 7 2

Question

A uniform rod of mass m and length ℓ is in equilibrium under the action of contact forces, gravity and tension in string as shown in the figure. LIST I LIST II (P) The tension is the string is (1) 7 2 mg ​ (Q) The frictional force acting on the rod is (2) 3 mg ​ (R) If the string is cut, then just after it normal reaction on the rod is (3) 6 mg ​ (S) Just before the string is cut, the normal reaction on the rod is (4) 2 3 ​ mg ​ (5) Zero

TestHub · Accepted Answer

(P) 2 mg ​ 4 ℓ ​ = T 4 3 ℓ ​ ⇒ T = 6 mg ​ (Q) f r ​ = mg 2 3 ​ ​ (R) N = 2 mg ​ × 7 4 ​ = 7 2 mg ​ (S) N = 2 mg ​ − 6 mg ​ = 3 mg ​

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Doubts & Discussion

JEE Main (2026)

LIST I	LIST II
(P) The tension is the string is	(1) $\frac{2 mg}{7}$
(Q) The frictional force acting on the rod is	(2) $\frac{mg}{3}$
(R) If the string is cut, then just after it normal reaction on the rod is	(3) $\frac{mg}{6}$
(S) Just before the string is cut, the normal reaction on the rod is	(4) $\frac{3 mg}{2}$
	(5) Zero