A metre stick is balanced on a knife-edge at its centre. When two coins, each of mass 5 g are put one on top of the other at the 12 cm mark, the stick is found to be balanced at 45.0 cm. What is the m

Question

A metre stick is balanced on a knife-edge at its centre. When two coins, each of mass 5 g are put one on top of the other at the 12 cm mark, the stick is found to be balanced at 45.0 cm. What is the mass (in gram) of the metre stick?

TestHub · Accepted Answer

Let total mass of the metre stick be M gram

Distance between mid-point E and new centre of gravity (DE),

= 50 - 45 = 5 cm

Distance between 12 cm mark and new centre of gravity (CD),

= 45 - 12 = 33 cm

From principle of moments in equilibrium,

Mg × DE = (2 × 5g) × CD

M × 5 = 10 × 33

or M = 66 g

∴ Mass of the metre stick is 66 g.

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