Find its linear speed(in m/s) at point C . If answer is y x find x + y :-

− mg 1 = 2 1 ( 5 7 mv 2 − 5 7 m 7 200 ) ∴ − 20 = 5 7 v 2 − 40 ∴ 7 100 = v

Physics - Rotation Question with Solution | TestHub

PhysicsRotationTranslational + RotationalMedium2 minQB

PhysicsMediumnumerical

Passage / Comprehension

A small sphere of mass $1 k g$ is rolling without slipping on a rough stationary base with linear speed $v = \frac{200}{7} m / s$ . It leaves the inclined plane at point C.

Find its linear speed(in m/s) at point C . If answer is $\frac{x}{y}$ find $x + y$ :-

Answer:

107.00

Solution:

$- mg 1 = \frac{1}{2} (\frac{7}{5} mv^{2} - \frac{7}{5} m \frac{200}{7})$

$∴ - 20 = \frac{7}{5} v^{2} - 40$

$∴ \frac{100}{7} = v$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Translational + Rotational

⏱ 2mℹ️ Source: QB

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