Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationMedium2 minQB

PhysicsMediummultiple choice

A uniform rod of mass ' m ' and length ' $Y$ is held horizontally by two vertical strings ' A ' and ' B ' of negligible mass and a small block of mass ' m ' is also placed on the top of the rod as shown in the figure. Then which of the following is/are correct?

Options:(select one or more)

Answer:

A, C, D

Solution:

$\frac{m g l}{4} = \frac{7}{48} m l^{2} α$ for rod alone

$α = \frac{12 g}{71} a_{B} = α \cdot \frac{3 l}{4} = \frac{9 g}{7} > g$

So, $N = 0$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: QB

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