A wheel of radius 0.2 m rotates freely about its center when a string that is wrapped over its rim is pulled by force of 10 N as shown in figure. The established torque produces an angular acceleratio

Question

A wheel of radius 0.2 m rotates freely about its center when a string that is wrapped over its rim is pulled by force of 10 N as shown in figure. The established torque produces an angular acceleration of $2 rad / s^{2}$ . Moment of inertia of the wheel is _____ $kg m^{2}$ .
(Acceleration due to gravity $= 10 m / s^{2}$ )

Question diagram: A wheel of radius 0.2 m rotates freely about its center when

Answer:

1.00

Solution:

$FR = I α \Rightarrow I = \frac{FR}{α} = \frac{10 \times 0.2}{2} = 1 kg - m^{2}$

TestHub · Accepted Answer

​ FR = I α ⇒ I = α FR ​ = 2 10 × 0.2 ​ = 1 kg − m 2 ​

Physics - Rotation Question with Solution | TestHub

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