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PhysicsRotationCalculation of M.I.Medium2 minPYQ_2024
PhysicsMediumnumerical

Two identical spheres each of mass2 kgand radius50 cmare fixed at the ends of a light rod so that the separation between the centers is150 cm. Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point isx20 kg m2, where the value ofxis

Question diagram: Two identical spheres each of mass 2 kg and radius 50 cm are
Answer:
53.00
Solution:

Using parallel axis theorem, we can write total moment of inertia as, I=25mR2+md2×2

I=225×2×122+2×342=5320 kg m2

Therefore, x=53.

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.
2mℹ️ Source: PYQ_2024

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