Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

A rod of mass m and length $ℓ$ is acted upon by two forces each of magnitude F as shown in the figure. The length of the rod is $ℓ$ , area of cross section is A , the Young's modulus of the material is Y . Select correct alternative(s).

Options:

Answer:

Solution:

Tension at a distance x from right and is T

$F - T = \frac{M}{ℓ} \times a = \frac{M}{ℓ} x . (\frac{2 F}{M}) T = (F - \frac{2 Fx}{ℓ})$ tension at mid point is zero.

For $x > \frac{ℓ}{2}$ stress is compressive.For $x > \frac{ℓ}{2}$ stress is tensile

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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