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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Medium2 minPYQ_2024

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The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is $2400 g cm^{2}$ . The length of the 400 g rod is nearly:NEET 2024

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Solution:

Moment of inertia of rod $= I = \frac{m ℓ ^{2}}{12}$ $\Rightarrow 2400 = 400 \frac{ℓ ^{2}}{12} \Rightarrow 72 = ℓ^{2} \Rightarrow ℓ = 72 = 8.48 cm ≃ 8.5 cm$

Stream:NEETSubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2024

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