Physics - Rotation Question with Solution | TestHub

Moment of inertia of circular ring about an axis passing through its centre of mass and perpendicular to its plane

$I=M{R}^2$

Here,$I=4 \mathrm{k}\mathrm{g} {\mathrm{m}}^2, m=1 \mathrm{k}\mathrm{g}$

$R^2=\frac{4}{1}=4$

or$R=2 \mathrm{m}$

Therefore, diameter of ring = 4 m.