Start Free Mock LoginAlready registered? Login here

Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationMedium2 minQB

PhysicsMediumsingle choice

A mass m = 1 kg hangs from the wheel of radius R = 1 m. When released from rest the mass falls through a height h = 2 m in 1 second. The moment of inertia of the wheel is (g = 10 m/s $^{2}$ ) :-

Options:

Answer:

Solution:

Mass falls from rest: $h = \frac{1}{2} a t^{2}$

$2 = \frac{1}{2} a (1)^{2} \Rightarrow a = 4 m/ s^{2}$

For the hanging mass:

$a = \frac{m g}{m + \frac{I}{R ^{2}}}$

$I = (\frac{g}{a} - 1) m R^{2}$

$I = (\frac{10}{4} - 1) (1) (1)^{2} = 1.5 kg m^{2}$

Answer: C

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...