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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Easy2 minPYQ_2023
PhysicsEasynumerical

A ring and a solid sphere rotating about an axis passing through their centres have same radii of gyration. The axis of rotation is perpendicular to plane of ring. The ratio of radius of ring to that of sphere is 2x. The value of x is _____.

Answer:
5.00
Solution:

The moment of inertia of the ring about an axis perpendicular to the plane of ring is Ir=mk2.

The moment of inertia of the sphere is 

Is=25mR2s

It is given that 

mk2=mR2r=25mRs2   ...(i)

From equation (i)

Rr=25Rs

From the question, it can be written that

RrRs=2x

RrRs=25x=5

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.
2mℹ️ Source: PYQ_2023

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