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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationEasy2 minPYQ_2021

PhysicsEasysingle choice

A uniform rod of length $200 cm$ and mass $500 g$ is balanced on a wedge placed at $40 cm$ mark. A mass of $2 kg$ is suspended from the rod at $20 cm$ and another unknown mass $m$ is suspended from the rod at $160 cm$ mark as shown in the figure. Find the value of $m$ such that the rod is in equilibrium. $(g = 10 m s^{- 2})$

NEET 2021

Options:

Answer:

Solution:

Balancing torque about the wedge, we get

$2 g \times 20 = 0.5 g \times 60 + m g \times 120$

$\Rightarrow 2 = 1.5 + 6 m$

$\Rightarrow m = \frac{0.5}{6} = \frac{1}{12} kg$

Stream:NEETSubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: PYQ_2021

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