Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsMedium2 minPYQ_2009

PhysicsMediumsingle choice

A thin uniform rod of length $ℓ$ and mass $m$ is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is $ω$ . Its centre of mass rises to a maximum height of

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Answer:

Solution:

$T.E = T . E_{f} \frac{1}{2} I ω^{2} = m g h \frac{1}{2} \times \frac{1}{3} m ℓ^{2} ω^{2} = m g h \Rightarrow h = \frac{1}{6} \frac{ℓ ^{2} ω ^{2}}{g}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2009

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