Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Easy2 minPYQ_2021

PhysicsEasysingle choice

Moment of inertia of a square plate of side $l$ about the axis passing through one of the corner and perpendicular to the plane of square plate is given by:

Options:

Answer:

Solution:

Use parallel axis theorem to get the magnitude of the moment of inertia of a square plate of side $l$ about the axis passing through one of the corners and perpendicular to the plane of a square plate,

$I_{z} = I_{cm} + M {(\frac{l}{\sqrt{2}})}^{2}$

$\Rightarrow I_{z} = \frac{M l^{2}}{6} + \frac{M l^{2}}{2} = \frac{4 M l^{2}}{6} = \frac{2 M l^{2}}{3}$ .

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2021

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