An object of mass ' m ' is projected from origin in a vertical x y plane at an angle 4 5 ∘ with the x axis with an initial velocity v 0 . The magnitude and direction of the angular momentu

Question

An object of mass ' m ' is projected from origin in a vertical $x y$ plane at an angle $4 5^{\circ}$ with the x axis with an initial velocity $v_{0}$ . The magnitude and direction of the angular momentum of the object with respect to origin, when it reaches at the maximum height, will be [ g is acceleration due to gravity]

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Answer:

C

Solution:

$H = \frac{( \frac{v _{0}}{2} ) ^{2}}{2 g} = \frac{v _{0}^{2}}{4 g} L = mvh L = m \frac{v _{0}}{2} \frac{v _{0}^{2}}{4 g}$

TestHub · Accepted Answer

​ H = 2 g ( 2 ​ v 0 ​ ​ ) 2 ​ = 4 g v 0 2 ​ ​ L = mvh L = m 2 ​ v 0 ​ ​ 4 g v 0 2 ​ ​ ​

Physics - Rotation Question with Solution | TestHub

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