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PhysicsRotationTranslational + RotationalHard2 minPYQ_2021
PhysicsHardnumerical

A circular disc reaches from top to bottom of an inclined plane of lengthL.When it slips down the plane, it takes timet1. When it rolls down the plane, it takes timet2. The value oft2t1is3x. The value ofxwill be

Question diagram: A circular disc reaches from top to bottom of an inclined pl
Answer:
2.00
Solution:

If disk slips on inclined plane, then its acceleration, a1=gsinθ
L=12a1t12
t1=2 La1 i

If disk rolls on inclined plane, its acceleration,
a2=gsinθ1+ImR2
a2=gsinθ1+mR22 mR2
a2=23gsinθ
Now L=12a2·t22
t2=2 La2 ii

Now, t2t1=a1a2=32
x=2

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Translational + Rotational
2mℹ️ Source: PYQ_2021

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