Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Easy2 minPYQ_2021

PhysicsEasysingle choice

Moment of inertia $(M . I .)$ of four bodies, having same mass and radius, are reported as;

$I_{1} = M . I .$ of thin circular ring about its diameter,

$I_{2} = M . I .$ of circular disc about an axis perpendicular to disc and going through the centre,

$I_{3} = M . I .$ of solid cylinder about its axis and

$I_{4} = M . I .$ of solid sphere about its diameter.

Then:

Answer:

Solution:

Ring $I_{1} = \frac{M R^{2}}{2}$ about diameter

Disc $I_{2} = \frac{M R^{2}}{2}$

Solid cylinder $I_{3} = \frac{M R^{2}}{2}$

Solid sphere $I_{4} = \frac{2}{5} M R^{2}$

$I_{1} = I_{2} = I_{3} > I_{4}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2021

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