One-fourth length of a uniform rod is placed on a rough horizontal surface and it starts rotating about the edge as soon as we release it. The rod starts slipping on the edge when it has turned throug

Question

One-fourth length of a uniform rod is placed on a rough horizontal surface and it starts rotating about the edge as soon as we release it. The rod starts slipping on the edge when it has turned through an angle $θ$ . If the coefficient of friction between rod and surface is $μ$ , and it satisfies the relation $x \tan θ = 4 μ$ , then what is the value of $x$ ? [Take $g = 10 m / s^{2}$ ]

TestHub · Accepted Answer

m g l 4 sin ⁡ θ = 1 2 I ω 2 α = m g l 4 cos ⁡ θ I μ N - m g sin ⁡ θ = m ω 2 l 4 m g cos ⁡ θ - N = m l 4 α Solving, 13 tan ⁡ θ = 4 μ .

Physics - Rotation Question with Solution | TestHub

Doubts & Discussion