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Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The moment of inertia of a solid cylinder about its axis is given by $\frac{1}{2} M R^{2}$ . If this cylinder rolls without shipping the ratio of its rotational kinetic energy to its translational kinetic energy is-

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Answer:

Solution:

$K_{R} = \frac{1}{2} I ω^{2} \Rightarrow K_{R} = \frac{1}{2} \times \frac{1}{2} m R^{2} \frac{v^{2}}{R^{2}} \Rightarrow K_{R} = \frac{1}{2} . \frac{1}{2} m v^{2}$

$K_{R} = \frac{1}{2} K_{T} \Rightarrow \frac{K_{R}}{K_{T}} = \frac{1}{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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