A uniform rod of length 75 cm is hinged at one of its ends and is free to rotate in vertical plane. It is released from rest when rod is horizontal. When the rod becomes vertical, it is broken at mid-

Question

A uniform rod of length 75 cm is hinged at one of its ends and is free to rotate in vertical plane. It is released from rest when rod is horizontal. When the rod becomes vertical, it is broken at mid-point without any jerk and lower part now moves freely. The distance of centre of lower part from hinge, when it again becomes vertical for the first time is r. Find the approximate value of 2r in meters

Answer:

5.00

Solution:

$t = \frac{π}{ω} = \frac{π}{40} sec . x = v_{0} t y = \frac{1}{2} gt^{2} r = x^{2} + (y + \frac{3 l}{4})^{2} ≃ 2.5 m$

TestHub · Accepted Answer

​ t = ω π ​ = 40 ​ π ​ sec . ​ x = v 0 ​ t ​ y = 2 1 ​ gt 2 ​ r = x 2 + ( y + 4 3 l ​ ) 2 ​ ≃ 2.5 m ​

Physics - Rotation Question with Solution | TestHub

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