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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCollision in RotationEasy2 minPYQ_2020

PhysicsEasysingle choice

The moment of inertia of a ring about an axis passing through the centre and perpendicular to its plane is $I$ . It is rotating with angular velocity $ω.$ Another identical ring is gently placed on it so that their centres coincide. If both the rings are rotating about the same axis then loss in kinetic energy is

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Answer:

Solution:

From conservation of angular momentum

$I_{1} ω_{1} = I_{2} ω_{2}$

$I ω = 2 I ω_{2}$

$ω_{2} = \frac{ω}{2}$

New $KE = \frac{1}{2} . (2 I) {(\frac{ω}{2})}^{2} = \frac{I ω^{2}}{4}$

Loss in $KE = \frac{1}{2} I ω^{2} - \frac{I ω^{2}}{4} = \frac{I ω^{2}}{4}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Collision in Rotation

⏱ 2mℹ️ Source: PYQ_2020

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