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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationMedium2 minPYQ_2020
PhysicsMediumnumerical

A forceF=(i^+2j^+3k^) Nacts at a point(4i^+3j^-k^) m. Then the magnitude of torque about the point(i^+2j^+k^) mwill bex N-m.The value ofxis..........

Answer:
195.00
Solution:

r=4-1i^+3-2j^+-1-1k^

=3i^+j^-2k^

τ=r×F=i^jk^31-2123

=i^7-j^11+k^5=7i^-11j^+5k^

=49+121+25=195

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration
2mℹ️ Source: PYQ_2020

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