Physics - Rotation Question with Solution | TestHub

Given,              M = 3 kg

R = 40 cm = 0.40 m

F = 30 N

Moment of inertia of the hollow cylinder about its axis of symmetry

I = MR²

= 3 × (0.40)²= 0.48 kg-m²

Torque acting on the cylinder by the applied force,

$\mathrm{\tau }$= F × R

= 30 × 0.40 = 12 N-m.

Angular acceleration produced in cylinder,

$\text{α}=\frac{\text{τ}}{\text{I}}=\frac{\text{12}}{\text{0.48}}={\text{25 rad/s}}^2$

Linear acceleration, a = R$\mathrm{\alpha }$

= 0.40 × 25 = 10.0 m/s²