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Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A rod of mass $M k g$ and length $L$ metre is bent in the form of an equilateral triangle. The moment of inertia of triangle about a vertical axis to perpendicular to the plane of triangle and passing through the centre (in units of $k g m^{2}$ ) is

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Answer:

Solution:

Moment of inertia of any one side about its perpendicular bisector is

$I_{cm} = \frac{1}{2} (\frac{M}{3}) {(\frac{L}{3})}^{2}$

Moment of inertia of this rod about about $O$

$I = I_{cm} + {Md}^{2}$

$I = [\frac{1}{12} (\frac{M}{3}) {(\frac{L}{3})}^{2} + (\frac{M}{3}) {(\frac{\frac{L}{3}}{2 \sqrt{3}})}^{2}]$

$I = \frac{{ML}^{2}}{162}$

Moment of Inertia of a triangle $= 3 I = \frac{{ML}^{2}}{54}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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