Start Free Mock LoginAlready registered? Login here

Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A body of mass $m$ slides down an incline and reaches the bottom with a velocity $v$ . If the same mass was in the form of a ring which rolls down this incline, the velocity of the ring at the bottom would have been

Options:

Answer:

Solution:

When body slides, $v = \sqrt{2 g h}$ ....(1)

When ring rolls, $v' = \sqrt{\frac{2 g h}{1 + k^{2} / r^{2}}} = \sqrt{\frac{2 g h}{2}} = \frac{v}{\sqrt{2}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...