A thin metal rod of mass 'M' and length 'L' is cut into 4 equal parts by cutting it perpendicular to its length, If moment of inertia of the rod about an axis passing through its c

Question

A thin metal rod of mass 'M' and length 'L' is cut into 4 equal parts by cutting it perpendicular to its length, If moment of inertia of the rod about an axis passing through its centre and perpendicular to its axis is 'I' then moment of inertia of each part about the similar axis is

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Answer:

D

Solution:

(C) $I = \frac{M L ^{2}}{12}$ $∴ \frac{I ^{'}}{I} = \frac{\frac{M}{4} \cdot ( \frac{L}{4} ) ^{2}}{M L ^{2}} = \frac{1}{64}$

TestHub · Accepted Answer

(C) I = 12 M L 2 ​ ∴ I I ′ ​ = M L 2 4 M ​ ⋅ ( 4 L ​ ) 2 ​ = 64 1 ​

Physics - Rotation Question with Solution | TestHub

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