Physics - Rotation Question with Solution | TestHub

${\text{I}}_0=\left(\frac{{\text{MR}}^2}{2}\right)$

${\text{I}}_0={\text{I}}_{\text{cm}}+{\text{Md}}^2$

$\frac{{\text{MR}}^2}{2}={\text{I}}_{\text{cm}}+\text{M}{\left(\frac{4\text{R}}{3\pi }\right)}^2$

$\Rightarrow {\text{I}}_{\text{cm}}=\frac{{\text{MR}}^2}{2}-\text{M}{\left(\frac{4\text{R}}{3\pi }\right)}^2$

${\text{I}}_{\text{cm}}=\left[\frac{{\text{MR}}^2}{2}-\text{M}{\left(\frac{4\text{R}}{3\pi }\right)}^2\right]$