A cylinder rest on a horizontal surface. A small particle of mass m is held in equilibrium by applying the force F as shown in figure (which is connected to massless string). The value of force F will be :-

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TestHub · Accepted Answer

For equilibrium of point mass, tension in string will be Mg .
For the equilibrium of cylinder

F = f

(horizontal)
For rotational equilibrium

Σ τ_{ext} = 0

FR + fR = T \times R

2 FR = mg \times R \Rightarrow F = \frac{mg}{2}

Physics - Rotation Question with Solution | TestHub

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JEE Main (2028)