Physics - Rotation Question with Solution | TestHub

Here,${\omega }_1=3\mathrm{\pi }{\text{rad s}}^{-1}\text{, }{\text{I}}_1=\text{I}$

${\text{I}}_2=\frac{75}{100}{\text{I}}_1=\frac{3}{4}\text{I, }{\omega }_2=\text{?}$

As${\text{I}}_2{\omega }_2={\text{I}}_1{\omega }_1$

$\therefore {\omega }_2=\frac{{\text{I}}_1}{{\text{I}}_2}\times {\omega }_1=\frac{4}{3}\times 3\pi =4\pi {\text{ rad s}}^{-1}$