Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A uniform sphere of mass $500 g$ rolls without slipping on a plane horizontal surface with its centre moving at a speed of $5.00 cm s^{- 1}$ . Its kinetic energy is:

Options:

Answer:

Solution:

$K . E$ of the sphere $=$ Translational $K . E +$ Rotational $K . E$
$= \frac{1}{2} {m v}^{2} (1 + \frac{K^{2}}{R^{2}}) K =$ Radius of gyration
$= \frac{1}{2} \times \frac{1}{2} \times {(\frac{2}{100})}^{2} (1 + \frac{2}{5})$
$= \frac{35}{4} \times 10^{- 4} J$
$= 8.75 \times 10^{- 4} J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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