Physics - Rotation Question with Solution | TestHub

The moment of inertia $I$ of a solid sphere about the axis of rotation through the centre is $I=\frac{2}{5}M{R}^2$ $\therefore$ Angular momentum $L=I\omega =\frac{2}{5}M{R}^2\times \frac{2\pi }{T}$ $=\frac{4\pi M{R}^2}{5T}$ where $T=$ time period of rotation