The angle between vectors A → and B → is 60 ° . What is the ratio of A → · B → and | A → × B → | ?

Now, = A → · B → | A → × B → | = AB cos θ AB sin θ = cot θ Since θ = 60 ° , A → · B → | A → × B → | = cot 60 ° = 1 3

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Physics - Rotation Question with Solution | TestHub

PhysicsRotationAngular momentumEasy2 minPYQ_2020

PhysicsEasysingle choice

The angle between vectors $\vec{A}$ and $\vec{B}$ is $60 °$ . What is the ratio of $\vec{A} \cdot \vec{B}$ and $| \vec{A} \times \vec{B} | ?$

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Answer:

Solution:

$Now, = \frac{\vec{A} \cdot \vec{B}}{| \vec{A} \times \vec{B} |} = \frac{AB cos θ}{AB sin θ} = cot θ$

Since $θ = 60 °$ ,

$\frac{\vec{A} \cdot \vec{B}}{| \vec{A} \times \vec{B} |} = cot 60^{°} = \frac{1}{\sqrt{3}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:RotationSubtopic:Angular momentum

⏱ 2mℹ️ Source: PYQ_2020

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