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Physics - Rotation Question with Solution | TestHub

PhysicsRotationTranslational + RotationalMedium2 minQB

PhysicsMediummultiple choice

In the figure shown, there is no friction between $m_{1}$ and the surface. In case 1, the pulley is massless. In case 2, pulley is massive and the string does not slip on the pulley. In both cases, string is massless.

Options:(select one or more)

Answer:

A, B, C

Solution:

Case 1: massless pulley, so both tensions are equal

$a_{1} = \frac{m _{2} g}{m _{1} + m _{2}}$

Case 2: massive pulley, torque equation:

$(T_{2} - T_{1}) R = I \frac{a}{R}$

So $T_{2} > T_{1}$

$a_{2} = \frac{m _{2} g}{m _{1} + m _{2} + \frac{I}{R ^{2}}}$

Hence $a_{1} > a_{2}$

Answer: A, B, C

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Translational + Rotational

⏱ 2mℹ️ Source: QB

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