The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N , and the distance of the particle from the origin is 5 m , the angle between the force

Question

The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N , and the distance of the particle from the origin is 5 m , the angle between the force and the position vector is (in radians):

TestHub · Accepted Answer

Torque about the origin = τ = r × F = r F sin θ ⇒ 2.5 = 1 × 5 sin θ sin θ = 0.5 = 2 1 ​ ⇒ θ = 6 π ​

Physics - Rotation Question with Solution | TestHub

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