Physics - Rotation Question with Solution | TestHub

$$\begin{array}{rl}& K.E_{\text{rotational }}=\frac{1}{2}I{\omega }^2\\ & =\frac{1}{2}\frac{2}{5}\omega r^2{d}^2\left(\because I_{\text{Solid sphere }}=\frac{2}{5}m{r}^2\right)\\ & K\cdot E_{\text{translational }}=\frac{1}{2}m{v}^2\\ & \therefore \frac{K\cdot E_{\text{rotational }}}{K\cdot E_{\text{translational }}}=\frac{2}{5}\end{array}$$ Hence option (b) is correct