Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsEasy2 minPYQ_2010

PhysicsEasysingle choice

For a particle in uniform circular motion the acceleration $a$ at a point $P (R, θ)$ on the circle of radius $R$ is (here $θ$ is measured from the $x$ -axis)

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Solution:

For a particle in uniform circular motion, $a = \frac{v ^{2}}{R} towards centre of circle ∴ a = \frac{v ^{2}}{R} (- cos θ \hat{i} - sin θ \hat{j}) or a = - \frac{v ^{2}}{R} cos θ \hat{i} - \frac{v ^{2}}{R} sin θ \hat{j}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2010

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