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Physics - Rotation Question with Solution | TestHub

PhysicsRotationRotational KinematicsHard2 minPYQ_2005

PhysicsHardsingle choice

A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity $v m / s$ . If it is to climb the inclined surface then $v$ should be

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Answer:

Solution:

From conservation of energy Potential energy $=$ translational kinetic energy + rotational kinetic energy $m g h = \frac{1}{2} m v^{2} + \frac{1}{2} (\frac{2}{5}) m R^{2} \cdot \frac{v ^{2}}{R ^{2}} \Rightarrow \frac{7}{10} m v^{2} = m g h \Rightarrow v \geq \frac{10}{7} g h$

Stream:AIIMSSubject:PhysicsTopic:RotationSubtopic:Rotational Kinematics

⏱ 2mℹ️ Source: PYQ_2005

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