Physics - Rotation Question with Solution | TestHub

For a rigid body rotating about a fixed axis, the angular momentum $L$ is given by $L=I\omega$, where $I$ is the moment of inertia about the axis of rotation and $\omega$ is the angular speed.

The moment of inertia of a uniform rod of mass $M$ and length $L$ about an axis passing through one end and perpendicular to its length is $I=\frac{1}{3}M{L}^2$. Therefore, the angular momentum about the pivot is $L=\frac{1}{3}M{L}^2\omega$.