Physics - Rotation Question with Solution | TestHub

PhysicsRotationTranslational + RotationalMedium2 minQB

PhysicsMediumsingle choice

In the following figure, a sphere of radius 3 m rolls on a plank. The accelerations of the sphere and the plank are indicated. The value of $α$ is

Answer:

Solution:

Rolling without slipping: the horizontal (tangential) acceleration of the contact point of the sphere equals the acceleration of the plank

Counterclockwise α gives the bottom point Rα to the right, and the centre moves 6 m/s² to the left

$a_{1} = R α - a_{2}$

$3 = 3 α - 6$

$α = 3 rad/ s^{2}$

Answer: A

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Translational + Rotational

⏱ 2mℹ️ Source: QB

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