Physics - Rotation Question with Solution | TestHub
PhysicsRotationCalculation of M.I.Medium2 minQB
PhysicsMediumsingle choice
Three identical rings of mass M and radius R are placed as shown in figure. The moment of inertia about axis xx' is

Options:
Answer:
B
Solution:
xx' is a diameter of the lower ring and is at distance R from the centre of each upper ring
Each ring about its own diameter: MR²/2
Answer: B
Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
