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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minQB

PhysicsMediumnumerical

A particle moves in the $x y$ -plane with constant acceleration $10 m / s^{2}$ along $- y$ ; its path is $y = x - \frac{x ^{2}}{80}$ (SI units). Its speed at the origin is:

Answer:

28.28

Solution:

$k_{2} = \frac{1}{80} : v_{x}^{2} = \frac{a}{2 k _{2}} = \frac{10 \times 80}{2} = 400, v_{x} = 20 m / s$ ;
$v_{y} = k_{1} v_{x} = 1 \times 20 = 20 m / s$ ;
$v = 400 + 400 = 202 = 28.3 m / s$ .

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: QB

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