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PhysicsKinematics2-D & 3DEasy2 minPYQ_2012

PhysicsEasysingle choice

A boy can throw a stone up to a maximum height of $10 m$ . The maximum horizontal distance that the boy can throw the same stone up to will be

Options:

Answer:

Solution:

maximum vertical height $= \frac{u ^{2}}{2 g} = 10 m$ Horizontal range of a projectile $= \frac{u ^{2} s i n 2 θ}{g}$ Range is maximum when $θ = 4 5^{\circ}$ Maximum horizontal range $= \frac{u ^{2}}{g}$ Hence maximum horizontal distance $= 20 m$ .

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2012

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