Physics - Practical physics Question with Solution | TestHub

PhysicsPractical physicsMiscellaneousEasy2 minQB

PhysicsEasysingle choice

In an experiment to determine the resistance of a galvanometer by half deflection method, the circuit shown is used. In one set of readings, if $R = 10 Ω$ and $S = 4 Ω$ , then the resistance of the galvanometer is

Options:

Answer:

Solution:

In 1st case,

$I_{1} = \frac{E}{R + G}$

In 2nd case,

$I_{2} = \frac{E}{R + \frac{S G}{S + G}}$

for half deflection,

$I_{2 G} = \frac{1}{2} I_{1}$

$\frac{1}{2} \frac{E}{R + G} = \frac{E}{R + \frac{S G}{S + G}} \frac{S}{S + G}$

$\Rightarrow G = \frac{R S}{R - S}$

$G = \frac{10 \times 4}{10 - 4} = \frac{20}{3} Ω$

Stream:JEESubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...