Physics - Practical physics Question with Solution | TestHub

$\text{V}={\text{2 f}}_0\left({\text{l}}_2-{\text{l}}_1\right)$

$\text{let}{\text{l}}_2-{\text{l}}_1=x$

${\text{l}}_1=\left(\text{24.0}\underset{¯}{+}\text{0.1}\right)\text{cm}$

${\text{l}}_2=\left(\text{74.70}\underset{¯}{+}\text{0.01}\right)\text{cm}$

${\text{l}}_2-{\text{l}}_1=\left(\text{50.70}\underset{¯}{+}\text{0.11}\right)\text{cm}$

$\frac{\Delta x}{x}=\left(\frac{\text{0.11}}{\text{50.70}}\right)$

$\Delta x\text{\%}=\frac{\text{0.11}}{\text{50.70}}\times \text{100}$

$=\text{0.22\%}$

$\Delta \text{V}\text{\%}=\Delta {\text{f}}_0\text{\%}+\Delta x\text{\%}$

$=\text{1.22}\text{\%}$

$=\text{1.2}\text{\%}$