There are 100 divisions on the circular scale of a screw gauge of pitch 1 mm . With no measuring quantity in between the jaws, the zero of the circular scale lies 5 divisions below the reference line.

Question

There are 100 divisions on the circular scale of a screw gauge of pitch $1 mm$ . With no measuring quantity in between the jaws, the zero of the circular scale lies 5 divisions below the reference line. The diameter of a wire is then measured using this screw gauge. It is found that 4 linear scale divisions are clearly visible while 60 divisions on circular scale coincide with the reference line. The diameter of the wire is :

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Answer:

C

Solution:

$Least count = \frac{1}{100} mm = 0.01 mm zero error = + 0.05 mm Reading = 4 \times 1 mm + 60 \times 0.01 mm - 0.05 mm = 4.55 mm$

TestHub · Accepted Answer

​ Least count = 100 1 ​ mm = 0.01 mm zero error = + 0.05 mm Reading = 4 × 1 mm + 60 × 0.01 mm − 0.05 mm = 4.55 mm ​

Physics - Error Question with Solution | TestHub

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