Physics - Practical physics Question with Solution | TestHub

The average value of the readings is $x_{\mathrm{avg}}=\frac{1.19+1.20+1.22+1.23}{4}=1.21$

Now, absolute error in measurement $\Delta x_{\mathrm{avg}}=\frac{0.02+0.01+0.01+0.02}{4}=\frac{0.06}{4}=0.015$

Percentage error in measurement is $=\frac{0.015}{1.21}\times 100\%$$=\frac{150}{121}\%$

So, the value of $x=150$.