Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter $D$ of a tube. The measured value of $D$ is:

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​ 10 MSD = 1 cm ; 1 MSD = 0.1 cm 7 MSD = 10 VSD 1 VSD = 0.07 cm Reading = 2 MSD − VSD = 0.2 cm − 0.07 cm = 0.13 cm ​ Ans. Option (C)

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