The Vernier constant of Vernier callipers is 0 . 1 mm and it has zero error of - 0 . 05 cm . While measuring diameter of a sphere, the main scale reading is 1 . 7 cm and coinciding vernier division is

Question

The Vernier constant of Vernier callipers is 0 . 1 mm and it has zero error of - 0 . 05 cm . While measuring diameter of a sphere, the main scale reading is 1 . 7 cm and coinciding vernier division is 5 . The corrected diameter will be _____ × 10 - 2 cm .

TestHub · Accepted Answer

Vernier constant is the least count of the vernier $V . C = 0.1 mm = 0.01 cm$

zero error $= - 0.05 cm$

$∴$ correction $= 0.05 cm$

$M . S . R . = 1.7 cm$

$V . S . R . = 5 V . C . = 5 \times 0.01 = 0.05 cm$

The diameter of the sphere will be,

diameter $= MSR + VSR +$ correction

$1.7 + 0.05 + 0.05 = 1.8 cm$

$= 180 \times 10^{- 2} cm$

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